document.write( "Question 971865: a conical funnel 12cm deep and 15cm in diameter is full of liquid.it is emptied into a cylindrical tin 10cm in diameter.find the height of the liquid in the tin \n" ); document.write( "
Algebra.Com's Answer #594284 by macston(5194)\"\" \"About 
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\"r%5Bco%5D\"=radius of cone=7.5cm; \"r%5Bcy%5D\"=radius of cylinder=5cm
\n" ); document.write( "\"h%5Bco%5D\"=height of cone=12cm; \"h%5Bcy%5D\"=height of liquid in cylinder
\n" ); document.write( "Volume of cone=\"%281%2F3%29%28pi%29r%5Bco%5D%5E2h%5Bco%5D\"
\n" ); document.write( "Volume in cylinder=\"%28pi%29r%5Bcy%5D%5E2h%5Bcy%5D\"
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\n" ); document.write( "Since volume of the cone = volume in the cylinder:
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\n" ); document.write( "\"%281%2F3%29%28pi%29r%5Bco%5D%5E2h%5Bco%5D=%28pi%29r%5Bcy%5D%5E2h%5Bcy%5D\" Divide each side by pi.
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\n" ); document.write( "\"%281%2F3%29r%5Bco%5D%5E2h%5Bco%5D=r%5Bcy%5D%5E2h%5Bcy%5D\" Divide each side by \"r%5Bcy%5D%5E2\"
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\n" ); document.write( "\"r%5Bco%5D%5E2h%5Bco%5D%2F%283r%5Bcy%5D%5E2%29=h%5Bcy%5D\" Put in values.
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\n" ); document.write( "\"%28%287.5cm%29%5E2%2812cm%29%29%2F%283%28%285cm%29%5E2%29%29=h%5Bcy%5D\"
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\n" ); document.write( "\"675cm%5E3%2F75cm%5E2=h%5Bcy%5D\"
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\n" ); document.write( "\"9cm=h%5Bcy%5D\"
\n" ); document.write( "ANSWER: The height of the liquid in the cylinder would be 9 centimeters.\r
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