document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971875>Question 971875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length and breadth of a rectangular are (5X +3) and (3X-2)cm. Write down in terms of X, <BR>\n" );
document.write( "(a) the perimeter <BR>\n" );
document.write( "(b) area. <BR>\n" );
document.write( "If the area of the rectangle is 230cm²,find the value of X and hence write down the perimeter of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594253 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P= 2L + 2W= 2(5X+3) +  2(3X-2) = 10X +6 +6X-4 =16X-2\r<BR>\n" );
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document.write( "AREA= L * W=15x^2-x-6\r<BR>\n" );
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document.write( "230=15x^2-x-6\r<BR>\n" );
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document.write( "15x^2-x-236=0\r<BR>\n" );
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document.write( "(15x+59) (x-4)=0<BR>\n" );
document.write( "first term will not make sense, as x <0<BR>\n" );
document.write( "x=4\r<BR>\n" );
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document.write( "Length is 23<BR>\n" );
document.write( "width is 10\r<BR>\n" );
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document.write( "Perimeter is twice their sum, or 66. </SPAN>\n" );
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