document.write( "Question 971854: Hello Tutor, I really need your help to answer this question please. \r
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Algebra.Com's Answer #594244 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"3+%2B+cos%282x%29\"\"%22%22=%22%22\"\"7%2F2\"\r\n" );
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document.write( "Clear the fraction by multiplying every term by 2\r\n" );
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document.write( "\"6+%2B+2cos%282x%29\"\"%22%22=%22%22\"\"7\"\r\n" );
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document.write( "Subtract 6 from both sides:\r\n" );
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document.write( "\"2cos%282x%29\"\"%22%22=%22%22\"\"1\"\r\n" );
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document.write( "Divide both sides by 2\r\n" );
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document.write( "\"cos%282x%29\"\"%22%22=%22%22\"\"1%2F2\"\r\n" );
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document.write( "Since \"1%2F2\" is positive, 2x is in QI or QIV\r\n" );
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document.write( "We want to include all but only all values of x on [0, 2π)\r\n" );
document.write( "which is the inequality:\r\n" );
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document.write( "\"0\"\"%22%22%3C=%22%22\"\"x\"\"%22%22%3C%22%22\"\"2pi\"\r\n" );
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document.write( "Since our equation involves 2x, not just x, we must multiply \r\n" );
document.write( "that inequality through by 2:\r\n" );
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document.write( "\"0\"\"%22%22%3C=%22%22\"\"2x\"\"%22%22%3C%22%22\"\"4pi\"\r\n" );
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document.write( "So all possibilities for 2x in that interval for\r\n" );
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document.write( "\"cos%282x%29\"\"%22%22=%22%22\"\"1%2F2\"\r\n" );
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document.write( "are\r\n" );
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document.write( "And we solve for x:\r\n" );
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document.write( "Edwn
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