document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971846>Question 971846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A researcher wishes to estimate the proportion of left-handers among a certain population. In a random sample of 900 people from the population, 74% are left-handed. Find the margin of error for the 95% confidence interval.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594238 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 sample proportion test CI\r<BR>\n" );
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document.write( "=p +/- z*SE\r<BR>\n" );
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document.write( "SE=sqrt{(.74)(.26)/900}\r<BR>\n" );
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document.write( "numerator is 0.74<BR>\n" );
document.write( "SE=0.0146<BR>\n" );
document.write( "95 % CI has z= +/-1.96\r<BR>\n" );
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document.write( "z*SE=.029\r<BR>\n" );
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document.write( "95% CI= 0.74 +/- 0.029   [0.711,0.769] </SPAN>\n" );
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