document.write( "Question 971813: Solve log25 125=x \n" ); document.write( "
Algebra.Com's Answer #594203 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! If one forgets how logs work\r \n" ); document.write( "\n" ); document.write( "log base 10 of 100=2\r \n" ); document.write( "\n" ); document.write( "10^2=100\r \n" ); document.write( "\n" ); document.write( "Do the same here \n" ); document.write( "25 ^x =125\r \n" ); document.write( "\n" ); document.write( "but 25 is 5^2\r \n" ); document.write( "\n" ); document.write( "(5^2)^x=125 \n" ); document.write( "5^2x=125 \n" ); document.write( "5^3=125\r \n" ); document.write( "\n" ); document.write( "2x=3 \n" ); document.write( "x=(3/2)\r \n" ); document.write( "\n" ); document.write( "25^(3/2)-125\r \n" ); document.write( "\n" ); document.write( "Key is recognizing that 25 can be written as 5^2.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |