document.write( "Question 971813: Solve log25 125=x \n" ); document.write( "
Algebra.Com's Answer #594203 by Boreal(15235)\"\" \"About 
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If one forgets how logs work\r
\n" ); document.write( "\n" ); document.write( "log base 10 of 100=2\r
\n" ); document.write( "\n" ); document.write( "10^2=100\r
\n" ); document.write( "\n" ); document.write( "Do the same here
\n" ); document.write( "25 ^x =125\r
\n" ); document.write( "\n" ); document.write( "but 25 is 5^2\r
\n" ); document.write( "\n" ); document.write( "(5^2)^x=125
\n" ); document.write( "5^2x=125
\n" ); document.write( "5^3=125\r
\n" ); document.write( "\n" ); document.write( "2x=3
\n" ); document.write( "x=(3/2)\r
\n" ); document.write( "\n" ); document.write( "25^(3/2)-125\r
\n" ); document.write( "\n" ); document.write( "Key is recognizing that 25 can be written as 5^2.\r
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