document.write( "Question 971816: A boy is now two-thirds as old as his sister, and two years ago he was five-eighths as old as she was then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #594202 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A boy is now two-thirds as old as his sister, and two years ago he was five-eighths as old as she was then. Find their present ages. \n" ); document.write( "--------------- \n" ); document.write( "Equations: \n" ); document.write( "b = (2/3)s \n" ); document.write( "b-2 = (5/8)(s-2) \n" ); document.write( "--------------------- \n" ); document.write( "Substitute and solve for \"s\":: \n" ); document.write( "(2/3)s - 2 = (5/8)s - (10/8) \n" ); document.write( "---------------- \n" ); document.write( "Multiply thru by 24 to get: \n" ); document.write( "16s - 48 = 15s - 30 \n" ); document.write( "---- \n" ); document.write( "s = 78 yrs (sister's age now) \n" ); document.write( "---- \n" ); document.write( "Solve for \"b\": \n" ); document.write( "b = (2/3)s \n" ); document.write( "b = (2/3)78 \n" ); document.write( "b = 52 yrs (boy's age now) \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |