document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971814>Question 971814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with Age and Quotient- Remainder word problems.\r<BR>\n" );
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document.write( "Here is my question:\r<BR>\n" );
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document.write( "A girl is now one-third as old as her mother, and in three years she will be two-fifths as old as her mother is then. Find their present ages.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594201 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we have two equations in two unknowns, let x be the girl and y be her mother, then<BR>\n" );
document.write( "x = y/3<BR>\n" );
document.write( "x + 3 = (2/5) * (y + 3)<BR>\n" );
document.write( "substitute for x in second equation<BR>\n" );
document.write( "y/3 + 3 = (2/5) * (y + 3)<BR>\n" );
document.write( "y/3 + 3 = 2y/5 + 6/5<BR>\n" );
document.write( "multiply both sides of = by 15<BR>\n" );
document.write( "5y + 45 = 6y + 18<BR>\n" );
document.write( "y = 27 and x = 9<BR>\n" );
document.write( "the girl is 9 and her mother is 27<BR>\n" );
document.write( "check the answer by substituting for x and y in the second equation<BR>\n" );
document.write( "9 + 3 = 2/5 * (27 + 3)<BR>\n" );
document.write( "12 = (2/5) * 30<BR>\n" );
document.write( "12 = 12<BR>\n" );
document.write( "answer checks </SPAN>\n" );
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