document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971817>Question 971817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is ninety-one. If the larger number is divided by the smaller number, then the quotient is fourteen and the remainder is one. Find the numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594199 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594199\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> numbers are x and y, y is larger.<BR>\n" );
document.write( " x+y=91\r<BR>\n" );
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document.write( "(y/x)=(14) +1   Be careful here.  The quotient is not 14 +1, it is 14 and there is one added to it.\r<BR>\n" );
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document.write( "multiply second by x<BR>\n" );
document.write( "y=(14x) +1<BR>\n" );
document.write( "substitute\r<BR>\n" );
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document.write( "x+ 14x + 1 = 91\r<BR>\n" );
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document.write( "15 x=90<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "y=85\r<BR>\n" );
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document.write( "85/6  = 14, remainder is 1\r<BR>\n" );
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document.write( "numbers are 6 and 85.<BR>\n" );
document.write( " </SPAN>\n" );
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