document.write( "Question 971783: assen can travel miles downstream in his motorboat in the same time he travels 3 miles upstream. if the current of the river is 3 mph, what is the boats rate in still water? write an equation that could be used to model this problem. let r represent the boats rate (in mph) in still water? \n" ); document.write( "
Algebra.Com's Answer #594174 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You missed a datum in the description. Not too bad an omission; I will generalize.\r
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\n" ); document.write( "\n" ); document.write( "r, speed of boat for still water, UNKNOWN
\n" ); document.write( "c, speed of river current
\n" ); document.write( "d, distance going downstream
\n" ); document.write( "u, distance going upstream
\n" ); document.write( "t, time to travel either direction, UNKNOWN\r
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\n" ); document.write( "\n" ); document.write( "___________________rate___________time__________distance
\n" ); document.write( "UPSTRM_____________r-c____________t_____________u
\n" ); document.write( "DOWNSTR____________r+c____________t_____________d\r
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\n" ); document.write( "\n" ); document.write( "\"system%28%28r-c%29t=u%2C%28r%2Bc%29t=d%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28t=u%2F%28r-c%29%2Ct=d%2F%28r%2Bc%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"u%2F%28r-c%29=d%2F%28r%2Bc%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"u%28r%2Bc%29=d%28r-c%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"ur%2Buc=dr-dc\"\r
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\n" ); document.write( "\n" ); document.write( "\"ur-dr=-dc-uc\"\r
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\n" ); document.write( "\n" ); document.write( "\"dr-ur=dc%2Buc\", which makes sense for the signs\r
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\n" ); document.write( "\n" ); document.write( "\"r%28d-u%29=dc%2Buc\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28r=%28dc%2Buc%29%2F%28d-u%29%29\"
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