document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971768>Question 971768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> bobs boat travels at 12 mph in still water. find the speed of the current if he go 4 miles upstream in the same time that it takes to go 8 miles downstream. write an equation that could be used to model this problem. let c represent the speed (in mph) of the current stream. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594160 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "12mph+c=speed downstream, 12mph-c=speed upstream<BR>\n" );
document.write( ".<BR>\n" );
document.write( "4miles/(12mph-c)=8miles/(12mph+c) Cross-multiply.<BR>\n" );
document.write( "96 mi^2/hr-8c miles=48mi^2/hr+4c miles Subtract 48mi^2/hr from each side<BR>\n" );
document.write( "48mi^2/hr-8c miles=4c miles Add 8c miles to each side.<BR>\n" );
document.write( "48mi^2/hr=12c miles Divide each side by 12 miles.<BR>\n" );
document.write( "4 mi/hr=c<BR>\n" );
document.write( "ANSWER: The rate of the current was 4 miles per hour.<BR>\n" );
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