document.write( "Question 971747: Five men can mow a square field who's side is 60 ft in 4 hours. At the same rate of work, compute how many hours 10 men could plow a square field who's side is 180 in feet? \n" ); document.write( "
Algebra.Com's Answer #594138 by josgarithmetic(39617)\"\" \"About 
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The rates are in units of square feet per hour.
\n" ); document.write( "Let r be the rate for 1 man.\r
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\n" ); document.write( "\n" ); document.write( "RT=A for rate time area.\r
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\n" ); document.write( "\n" ); document.write( "\"5r%2A4=60%5E2\", the first sentence.\r
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\n" ); document.write( "\n" ); document.write( "unknown number of hours t:
\n" ); document.write( "\"10r%2At=180%5E2\", the question, second sentence.\r
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\n" ); document.write( "\n" ); document.write( "This is a Uniform Rates problem, and does not involve any quadratic equation. The second equation, although contains a term of \"rt\", is still not quadratic.\r
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\n" ); document.write( "\n" ); document.write( "Be sure you study the discussion given and understand it. Once done, the first equation lets you solve for r, and then substitute for r in the second equation, and solve that one for t.
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