document.write( "Question 970599: x^log a base 2 + a^log x base2 = 2a^2
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Algebra.Com's Answer #594098 by anand429(138)\"\" \"About 
You can put this solution on YOUR website!
Already solved,but here it is again if u missed it.
\n" ); document.write( "\"x%5E%28log%282%2Ca%29%29%2Ba%5E%28log%282%2Cx%29%29=2a%5E2\"
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\n" ); document.write( "=> x^(log(x,a)/log(x,2))+\"a%5E%28log%282%2Cx%29%29=2a%5E2\" (using \"%28log%28a%2Cb%29%29=%28%28log%28x%2Cb%29%29%2F%28log%28x%2Ca%29%29%29\"
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\n" ); document.write( "=> a^(1/(log(x,2)))+\"a%5E%28log%282%2Cx%29%29=2a%5E2\"
\n" ); document.write( "=> \"a%5E%28log%282%2Cx%29%29%2Ba%5E%28log%282%2Cx%29%29=2a%5E2\"
\n" ); document.write( "=> \"2a%5E%28log%282%2Cx%29%29=2a%5E2\"
\n" ); document.write( "Comparing exponents, we get,
\n" ); document.write( "\"%28log%282%2Cx%29%29=2\"
\n" ); document.write( "=> \"x=2%5E2\"
\n" ); document.write( "=> \"x=4\"
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