document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971695>Question 971695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a jar contains n nikles and d dimes. there is a total of 200 coins in the jar.the value of the cions is $14.00.how manu nickles and how many dimes are in the jar?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594089 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> will do with 2 variables.\r<BR>\n" );
document.write( "\n" );
document.write( "n+d=200<BR>\n" );
document.write( ".05 n + .10 d= 14.00\r<BR>\n" );
document.write( "\n" );
document.write( "n=200-d\r<BR>\n" );
document.write( "\n" );
document.write( ".05 (200-d) +.10d=14.00\r<BR>\n" );
document.write( "\n" );
document.write( "10.00-.05d +.10d=14.00\r<BR>\n" );
document.write( "\n" );
document.write( ".05d =4.00, by collecting terms<BR>\n" );
document.write( "5d=400  after multiplying by 100.<BR>\n" );
document.write( "d=80<BR>\n" );
document.write( "n=120\r<BR>\n" );
document.write( "\n" );
document.write( "120*.05 =$6 for nickels<BR>\n" );
document.write( "80 dimes=$8<BR>\n" );
document.write( "Total $14 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );