document.write( "Question 971679: A regular hexagon ABCDEF has vertices at A(4,4√3), B(8,4√3), C(10,2√3), D(8,0), E(4,0), and F(2,2√3). Suppose the sides of the hexagon are reduced by 40% to produce a similar regular hexagon. What are the perimeter and area of the smaller hexagon rounded to the nearest tenth? \n" ); document.write( "
Algebra.Com's Answer #594080 by Alan3354(69443)\"\" \"About 
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A regular hexagon ABCDEF has vertices at A(4,4√3), B(8,4√3), C(10,2√3), D(8,0), E(4,0), and F(2,2√3). Suppose the sides of the hexagon are reduced by 40% to produce a similar regular hexagon. What are the perimeter and area of the smaller hexagon rounded to the nearest tenth?
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\n" ); document.write( "Find the lengths of the sides.
\n" ); document.write( "eg, AB = 4
\n" ); document.write( "\"BC+=+sqrt%28%282sqrt%283%29%29%5E2+%2B+2%5E2%29\" = 4
\n" ); document.write( "It's a regular hexagon, all sides = 4
\n" ); document.write( "Perimeter = 6*4 = 24 units
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\n" ); document.write( "\"Area+=+ns%5E2%2Acot%28180%2Fn%29%2F4\" where n = 6 & s = 4
\n" ); document.write( "Area =~ 41.5692 sq units
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\n" ); document.write( "Reducing by 40% --> 0.6*Perimeter
\n" ); document.write( "P = 24*0.6 = 14.4 units
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\n" ); document.write( "Area is a function of the square of the side length --> 0.36 x original
\n" ); document.write( "Area = 41.5692*0.6^2
\n" ); document.write( "Area =~ 14.965 sq units
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