document.write( "Question 971646: Find the approximate solution of this system of equations.\r
\n" ); document.write( "\n" ); document.write( "y = |x^2 − 3x + 1|
\n" ); document.write( "y = x − 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a. (1, 0)
\n" ); document.write( "b. (4.5, 3.5)
\n" ); document.write( "c. (2, 1)
\n" ); document.write( "d. (3.4, 2.3)
\n" ); document.write( "e. (0.6, -0.4)
\n" ); document.write( "

Algebra.Com's Answer #594078 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
The absolute value equation has two critical values for x, the roots.
\n" ); document.write( "\"%283%2B-+sqrt%285%29%29%2F2\"; to the left and right of the roots the equation is \"y=x%5E2-3x%2B1\" and between them is \"y=-x%5E2%2B3x-1\". You just want to find in which interval of x does the line y=x-1 intersect the absolute value equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Try testing for the middle interval first.
\n" ); document.write( "\"system%28y=x-1%2Cy=-x%5E2%2B3x-1%29\"
\n" ); document.write( "\"x-1=-x%5E2%2B3x-1\"
\n" ); document.write( "**\"-x%5E2%2B3x-x=0\"
\n" ); document.write( "\"x%5E2-3x%2Bx=0\"
\n" ); document.write( "\"x%5E2-2x=0\"
\n" ); document.write( "x=0 or x=1/2
\n" ); document.write( "(**this must be a mistake.)
\n" ); document.write( "Where is each of these two solutions? To left of the smaller critical value? To the right of the greater critical value? Between the two critical values?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solution to the problem not finished, but you should understand this strategy.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-3%2C3%2C-3%2C3%2Cx-1%2Cabs%28x%5E2-3x%2B1%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Once the mistake is corrected, you should find as shown in the graph, the solution is point (2,1).
\n" ); document.write( "
\n" );