document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971661>Question 971661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A girl asks her mother's age and is told, \"Six years ago I was nine times your age.  Now I am only three times your age.\"  What are the present ages of the girl and her mother? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #594062 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=594062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> girl's age now is x<BR>\n" );
document.write( "Her mother's age now is 3x\r<BR>\n" );
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document.write( "x-6 was her prior age <BR>\n" );
document.write( "(x-6)*9 was her mother's age.\r<BR>\n" );
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document.write( "The difference in their ages is 2x and always has been.\r<BR>\n" );
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document.write( "Therefore, (x-6)*9 - (x-6) =2x<BR>\n" );
document.write( "9x-54 -x +6 =2x<BR>\n" );
document.write( "6x=48 by collecting terms and moving the constants to the other side.\r<BR>\n" );
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document.write( "x=8<BR>\n" );
document.write( "mother is 24\r<BR>\n" );
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document.write( "6 years ago, girl was 2<BR>\n" );
document.write( "mother was 18\r<BR>\n" );
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document.write( " </SPAN>\n" );
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