document.write( "Question 971596: Could someone please help me with this problem, because I need to turn x into a quadratic equation when a=1
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\n" ); document.write( "I had solved and got the equation \"x%5E2%2B16x%2B16\" because I originally decided to start with (x+4)(x+4), but as an answer for \"x%5E2%2B16x%2B16\", I had some decimals, so I don't know which part I did wrong.
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Algebra.Com's Answer #594045 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
(x+4)*(x+4) = x^2 + 8x + 16\r
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\n" ); document.write( "\n" ); document.write( "(x-4)*(x-4) = x^2 - 8x + 16\r
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\n" ); document.write( "\n" ); document.write( "i believe the factors needed to be (x-4) * (x-4) because, when you solve for x, you then get x = 4.\r
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\n" ); document.write( "\n" ); document.write( "(x-4)*(x-4) = 0\r
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\n" ); document.write( "\n" ); document.write( "set each of the factors equal to 0 to get:\r
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\n" ); document.write( "\n" ); document.write( "x-4 = 0
\n" ); document.write( "x-4 = 0\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 4
\n" ); document.write( "x = 4\r
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\n" ); document.write( "\n" ); document.write( "if x = 4, then the factor has to be x-4 because x-4 = 0\r
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\n" ); document.write( "\n" ); document.write( "when you have the solution and you want to convert it into a factor, you have to set the equation equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "start with x = 4
\n" ); document.write( "subtract 4 from both sides of the equation to get x - 4 = 0
\n" ); document.write( "that's your factor.\r
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