document.write( "Question 971583: If 3i is a zero of f(x)= x^4-2x^3+6x^2-18x-27, find all the zeros and write the answer in factored form. Thanks \n" ); document.write( "
Algebra.Com's Answer #594016 by Boreal(15235)\"\" \"About 
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f(x)= x^4-2x^3+6x^2-18x-27\r
\n" ); document.write( "\n" ); document.write( "(x+3i) (x-3i) are factors, since they are conjugate.\r
\n" ); document.write( "\n" ); document.write( "These multiply to x^2-9i^2=x^2+9\r
\n" ); document.write( "\n" ); document.write( "The other factor must contain a -3, since the constant is -27\r
\n" ); document.write( "\n" ); document.write( "Divide that into the original polynomial, and we get x^2-2x-3= (x-3) (x+1)\r
\n" ); document.write( "\n" ); document.write( "The zeros are +/- 3i , 3, -1 . The latter two produce 0 in the polynomial.\r
\n" ); document.write( "\n" ); document.write( "The factored form is (x+3i)(x-3i)(x-3)(x+1)\r
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