document.write( "Question 82815: i am still working on homework and i need help with another problem if someone has a kind enought heart to help!! the problem is:\r
\n" ); document.write( "\n" ); document.write( "6x^2_<20+7x thats one of those less than or equal things, now do i need to get the 6x^2 on the other side and set it to zero and solve it like a quadratic?
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Algebra.Com's Answer #59398 by mjvictoria07(2)\"\" \"About 
You can put this solution on YOUR website!
Here it is....\r
\n" ); document.write( "\n" ); document.write( "Ok you transfer 6x^2 to the other side...
\n" ); document.write( "It becomes\r
\n" ); document.write( "\n" ); document.write( "\"0_%3C20%2B7x-6x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Not that the solution set of the answer CANNOT be described in terms of for numbers and values. It can only be described by a graph.\r
\n" ); document.write( "\n" ); document.write( "To find the solution set and\ show it with a graph, you first find the vertex (h,k) of the quadratic equation. Probably it is a parabola facing downward. Next use test point (0,0) and subtitute it. \r
\n" ); document.write( "\n" ); document.write( "Hence if we substitute it, we will have:\r
\n" ); document.write( "\n" ); document.write( "\"0_%3C20\", which is true. Hence the soluton set would be the graph of the parabola shaded on the part where (0,0) belongs.\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+20%2B7x-6x%5E2%29+\"\r
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