document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971451>Question 971451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can anyone help me figure this out?\r<BR>\n" );
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document.write( "Period of a Pendulum The period T(in seconds) of a simple pendulum as a function of its length l (in feet) is given by 32.2 ( ) 2 l T l = &#960; <BR>\n" );
document.write( "(a) Express the length l as a function of the period T. <BR>\n" );
document.write( "(b) How long is a pendulum whose period is 3 seconds?\r<BR>\n" );
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document.write( "Thank you in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593923 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> T(l) = 2pi * square root(l/g) where g is 32.2 feet per second per second<BR>\n" );
document.write( "now solve for l<BR>\n" );
document.write( "a) T/(2pi) = square root(l/g)<BR>\n" );
document.write( "square both sides of =<BR>\n" );
document.write( "(T/(2pi))^2 = l/32.2<BR>\n" );
document.write( "l = 32.2 * (T/(2pi))^2<BR>\n" );
document.write( "b) if T (period) is 3 seconds then<BR>\n" );
document.write( "l = 32.2 * (3/(2pi))^2 <BR>\n" );
document.write( "l = 32.2 * 0.227972663<BR>\n" );
document.write( "l = 7.340719753<BR>\n" );
document.write( "length of pendulum is 7.340719753 feet<BR>\n" );
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