document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971378>Question 971378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> not sure if you can help...\r<BR>\n" );
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document.write( "I need to find dy/dx at the point (0,1), if y^5=(x+2)^4 + e^x Iny-15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593918 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(570)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  y^5=(x+2)^4 + e^x Iny-15<BR>\n" );
document.write( "Differentiating on both sides with respect to x we get,<BR>\n" );
document.write( "5y^4(dy/dx)=4(x+2)^3+e^x.lny+e^x/y*(dy/dx)<BR>\n" );
document.write( "Substituting x=0 and y=1 in the above we get,<BR>\n" );
document.write( "5(dy/dx)=4(2)^3+e^0.ln(1)+e^0/1*(dy/dx)<BR>\n" );
document.write( "5(dy/dx)=32+1(0)+(dy/dx)<BR>\n" );
document.write( "4(dy/dx)=32<BR>\n" );
document.write( "(dy/dx)=8<BR>\n" );
document.write( "Answer=8 </SPAN>\n" );
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