document.write( "Question 971440: √1+cosA/√1-CosA=sinA/1-cosA
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Algebra.Com's Answer #593915 by amarjeeth123(570)\"\" \"About 
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LHS=√1+cosA/√1-CosA
\n" ); document.write( "Multiplying numerator and denominator by √1-CosA we get,
\n" ); document.write( "LHS=√1+cosA.√1-CosA/√1-CosA.√1-CosA=√1-cosA^2/√(1-cosA)^2=√sinA^2/(1-cosA)=sinA/(1-cosA)=RHS
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