document.write( "Question 971063: Two circles have their centres on the line y+3=0 and touch the line 3y-2x=0. If the radii of circles are \sqrt{13}
\n" ); document.write( "Find the equations of the circle and the coordinates of their centres
\n" ); document.write( "Hint use similar triangles.
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Algebra.Com's Answer #593887 by anand429(138)\"\" \"About 
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Since centres of circles lie on y+3=0, i.e y= -3
\n" ); document.write( "Let coordinates of centres be (x,-3)
\n" ); document.write( "Since the circles touch the line -2x+3y=0
\n" ); document.write( "So, the distance from centre of circles to this line are radii of circles.
\n" ); document.write( "So, Using the distance formula i.e \r
\n" ); document.write( "\n" ); document.write( "(|-2x+3*(-3)|)/(sqrt((-2^2)+3^2)) = sqrt(13) (|..| = mod sign)
\n" ); document.write( "or, |-2x+3*(-3)| = 13
\n" ); document.write( "or, -2x-9 = (+-13)
\n" ); document.write( "So, \"-2x-9+=+13\" -(i) or \"-2x-9+=+-13\"- (ii)
\n" ); document.write( "Solving both eqns. separately,
\n" ); document.write( "we get, \"x=+-11\" or \"x=2\"
\n" ); document.write( "So, the coordinates of center are (-11,-3) and (2,-3)
\n" ); document.write( "Equations of circles are \"%28x%2B11%29%5E2+%2B+%28y%2B3%29%5E2+=+13\" and \"%28x-2%29%5E2+%2B+%28y%2B3%29%5E2+=+13\"
\n" ); document.write( "i.e. \"x%5E2+%2B+y%5E2+%2B+22x+%2B+6y+-117+=0\" and \"x%5E2+%2B+y%5E2+-+4x+%2B+6y+=0\"
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