document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971416>Question 971416</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Osei is 12 years old and his father is 38years.\r<BR>\n" );
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document.write( "(i) In how many years will the father be twice as old as OSei?<BR>\n" );
document.write( "(ii)What would be Osei's age then? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593886 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "O=Osei's age=12yrs; F=Father's age=38yrs; x=years until father is twice as old<BR>\n" );
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document.write( "F+x=2(O+x) Plug in values.<BR>\n" );
document.write( "38yrs+x=2(12yrs+x)<BR>\n" );
document.write( "38yrs+x=24yrs+2x Subtract (24yrs+x) from each side.<BR>\n" );
document.write( "14yrs=x<BR>\n" );
document.write( "ANSWER 1: In 14 years, Father will be twice as old as Osei<BR>\n" );
document.write( "ANSWER 2: In 14 years, Osei will be (12yrs+14yrs) 26 years old,<BR>\n" );
document.write( "and Father will be (38yrs+14yrs) 52 years old. <BR>\n" );
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