document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971306>Question 971306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> give the domain and range of the following linear and quadratic <BR>\n" );
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document.write( "1. Linear. Y = 4/(x-7)<BR>\n" );
document.write( "2. Quadratic, Y=3x2+ 2x -3. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593840 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Domain is all reals except x=7 (denominator becomes 0)<BR>\n" );
document.write( "Range is all reals.\r<BR>\n" );
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document.write( "Domain is all x's for quadratic   <BR>\n" );
document.write( "Range  vertex has x-value of -b/2a  or -1/3<BR>\n" );
document.write( "At that x-value, y = (1/9)*3 -2/3 -3= -3 1/3\r<BR>\n" );
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document.write( "Range is y> (-10/3)\r<BR>\n" );
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