document.write( "Question 971285: 69 coins together the total value is 12$ the number of dimes plus the twice number of nickels is 33.5 more than the value of the quarters how many quarters dimes and nickels do you have? \n" ); document.write( "
Algebra.Com's Answer #593827 by stanbon(75887)\"\" \"About 
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69 coins together the total value is 12$ the number of dimes plus the twice number of nickels is 33.5 more than the value of the quarters how many quarters dimes and nickels do you have?
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\n" ); document.write( "Quantity:: n + d + q = 69 coins
\n" ); document.write( "Value:::: 5n +10d+25q = 1200 cents
\n" ); document.write( "Mix:: d + 2n = 25q+33.5
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\n" ); document.write( "Note:: The statement of the problem does
\n" ); document.write( "not result in positive whole-number values
\n" ); document.write( "for the number of nickels, dimes, and quarters.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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