document.write( "Question 971285: 69 coins together the total value is 12$ the number of dimes plus the twice number of nickels is 33.5 more than the value of the quarters how many quarters dimes and nickels do you have? \n" ); document.write( "
Algebra.Com's Answer #593827 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 69 coins together the total value is 12$ the number of dimes plus the twice number of nickels is 33.5 more than the value of the quarters how many quarters dimes and nickels do you have? \n" ); document.write( "--------------- \n" ); document.write( "Quantity:: n + d + q = 69 coins \n" ); document.write( "Value:::: 5n +10d+25q = 1200 cents \n" ); document.write( "Mix:: d + 2n = 25q+33.5 \n" ); document.write( "------------------------------ \n" ); document.write( "Note:: The statement of the problem does \n" ); document.write( "not result in positive whole-number values \n" ); document.write( "for the number of nickels, dimes, and quarters. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------------ \n" ); document.write( " \n" ); document.write( " |