document.write( "Question 971286: Flying against the wind, an airplane travels 8640 km in 9 hours. Flying with the wind, the same plane travels 5900 km in 5 hours. What is the rate of the plane in still air and what is the rate of the wind?
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Algebra.Com's Answer #593819 by Boreal(15235) $\"\"$ $\"About$

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Let x= speed of plane
\n" ); document.write( "Let y = speed of wind\r
\n" ); document.write( "\n" ); document.write( "9 (x-y)= 9x - 9y=8640 km units km/h * hr for constant*variable
\n" ); document.write( "5 (x+y)= 5x + 5y =5900\r
\n" ); document.write( "\n" ); document.write( "Divide first by 9; divide second by 5\r
\n" ); document.write( "\n" ); document.write( "x-y=960
\n" ); document.write( "x+y=1180 ;; now add them\r
\n" ); document.write( "\n" ); document.write( "2x = 2140
\n" ); document.write( "x=1070 km/h still air speed
\n" ); document.write( "1070-y=960
\n" ); document.write( "y=110 km/h\r
\n" ); document.write( "\n" ); document.write( "add them (1180) ; multiply by 5=5900 km
\n" ); document.write( "subtract them (960), multiply by 9=8640 km \r
\n" ); document.write( "\n" ); document.write( "Plane goes 1070 km/h
\n" ); document.write( "Wind speed is 110 km/h\r
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