document.write( "Question 971276: A person leaves home at 7:00 a.m. and drives to a destination at a rate of forty mph. After spending one hour at the destination, the person returns at a rate of twenty-five mph and arrives home at 2:30 p.m. How far is the trip to the destination? \n" ); document.write( "
Algebra.Com's Answer #593814 by JoelSchwartz(130)![]() ![]() ![]() You can put this solution on YOUR website! t=the time it took to get to the destination traveling forty miles per hour. \n" ); document.write( "x=amount of time it took to return home from the destination traveling twenty five miles per hour. \n" ); document.write( "t+1+x=7.5 \n" ); document.write( "t+x=6.5 \n" ); document.write( "d=number of miles each way \n" ); document.write( "40t=d \n" ); document.write( "25x=d \n" ); document.write( "25x=40t \n" ); document.write( "t=6.5-x \n" ); document.write( "25x=40(6.5-x) \n" ); document.write( "25x=260-40x \n" ); document.write( "65x=260 \n" ); document.write( "x=4 \n" ); document.write( "d=25*4 \n" ); document.write( "The trip is 100 miles to the destination. To go back to where the person started from it would take 200 miles of traveling. \n" ); document.write( " |