document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971270>Question 971270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have figured out the following:\r<BR>\n" );
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document.write( "What size is the interior angle of a regular 15-sided polygon?\r<BR>\n" );
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document.write( "n-2 (180)<BR>\n" );
document.write( "15-2 (180)<BR>\n" );
document.write( "13 (180)<BR>\n" );
document.write( "13(180)<BR>\n" );
document.write( "2340 degrees\r<BR>\n" );
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document.write( "Now, if one side has a length of 5 feet what is the perimeter?\r<BR>\n" );
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document.write( "Can you help?\r<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "George </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593808 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20850)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Since all the angles are equal, each direction-change is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360%2Fn ALIGN=MIDDLE  ALT=\"360%2Fn\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and that means that each interior angle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180 ALIGN=MIDDLE  ALT=\"180\"   DISABLED_style= \"max-width:90%; height:auto;\" >º minus this amount, or\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180+-+360%2Fn+ ALIGN=MIDDLE  ALT=\"180+-+360%2Fn+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=n=15 ALIGN=MIDDLE  ALT=\"n=15\"   DISABLED_style= \"max-width:90%; height:auto;\" > we will have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180+-360%2F15+=+180+-24+=+156 ALIGN=MIDDLE  ALT=\"180+-360%2F15+=+180+-24+=+156\"   DISABLED_style= \"max-width:90%; height:auto;\" >º \r<BR>\n" );
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document.write( "then, the sum of all internal angles is: <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+15%2A180+-+360=2340 ALIGN=MIDDLE  ALT=\"+15%2A180+-+360=2340\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "--------------<BR>\n" );
document.write( "if one side has a length of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5ft ALIGN=MIDDLE  ALT=\"5ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >,and we have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15 ALIGN=MIDDLE  ALT=\"15\"   DISABLED_style= \"max-width:90%; height:auto;\" > sides, then the perimeter is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2A5ft=75ft ALIGN=MIDDLE  ALT=\"15%2A5ft=75ft\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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