document.write( "Question 82784: PROBLEM\r
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document.write( "A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
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document.write( "Woman= h+5
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document.write( "Husband= h
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document.write( "Daughter=h+5/10(I think)
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document.write( " 100 \r
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document.write( "(h+5)+(h)+(h+5/10)=100
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document.write( " 2h+5+(h+5/10)=100
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document.write( " 3h+10=1000
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document.write( " 3h/3=990/3
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document.write( " h=330\r
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document.write( "My question is what did i do wrong I know that this is way too high of a number and I can't figure out where I went wrong. Thanks
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Algebra.Com's Answer #59379 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now? \n" ); document.write( "----------- \n" ); document.write( "NOW DATA: \n" ); document.write( "Let the daughter's age be \"x\". \n" ); document.write( "Mother age is 10x \n" ); document.write( "Husbands age is 10x-5 \n" ); document.write( "--------------------- \n" ); document.write( "14 Years from now DATA: \n" ); document.write( "Daughter's age will be x+14 \n" ); document.write( "Mothers age will be 10x+14 \n" ); document.write( "Husbands age will be 10x-5+14 = 10x+9 \n" ); document.write( "------------------- \n" ); document.write( "EQUATIOn: \n" ); document.write( "x+14 + 10x+14 + 10x+9 = 100 \n" ); document.write( "21x+37=100 \n" ); document.write( "21x = 63 \n" ); document.write( "x=3 (daughter's age NOW) \n" ); document.write( "10x = 30 (mother's age NOW) \n" ); document.write( "10x-5 = 25 (husband's age NOW) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |