document.write( "Question 971219: (x-2)^2+4y^2=16
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document.write( "I need to get the center, the vertices, and foci. \n" );
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Algebra.Com's Answer #593788 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! (x-2)^2+4y^2=16\r \n" ); document.write( "\n" ); document.write( "divide by 16\r \n" ); document.write( "\n" ); document.write( "x^2/16 +4y^2/16 =1= x^2/16 + y^2/4\r \n" ); document.write( "\n" ); document.write( "This is an ellipse centered on the origin.\r \n" ); document.write( "\n" ); document.write( "The x-axis goes from (-4,0) to (0,4). \n" ); document.write( "The y-axis goes from (0-2) to (0,2) Those points are the vertices.\r \n" ); document.write( "\n" ); document.write( "The foci are \n" ); document.write( "f=(sqrt (16-4))=2 sqrt (3)\r \n" ); document.write( "\n" ); document.write( "They are along the x-axis at (-2sqrt(3),0) and (2 sqrt (3),0) \n" ); document.write( "2sqrt(3)=3.464\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |