document.write( "Question 971246: how do u do substitution for systems of equations when one line is a quadratic \n" ); document.write( "
Algebra.Com's Answer #593786 by Theo(13342)\"\" \"About 
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same way as for two linear equations.
\n" ); document.write( "the substitution, however, should be done with the linear equation rather than the quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "y = x + 1
\n" ); document.write( "y = x^2 + 2x + 1\r
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\n" ); document.write( "\n" ); document.write( "replace y with x + 1 to get x + 1 = x^2 + 2x + 1
\n" ); document.write( "subtract x and subtract 1 from both sides of the equation to get:
\n" ); document.write( "x^2 + x = 0
\n" ); document.write( "factor out the x to get x * (x+1) = 0
\n" ); document.write( "solve for x to get x = 0 or x = -1\r
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\n" ); document.write( "\n" ); document.write( "when x = 0, x + 1 = 1 and x^2 + 2x + 1 = 1
\n" ); document.write( "when x = -1, x + 1 = 0 and x^2 + 2x + 1 = 1 - 2 + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "you have a common solution of x = 0 and x = -1.\r
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\n" ); document.write( "\n" ); document.write( "solve for y or x in the linear equation and then use that value to substitute in the quadratic equation.
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