document.write( "Question 971235: the larger of two integers is 1 less than twice the smaller. if twice the square of the smaller is increased by the larger,the result is 39 \n" ); document.write( "
Algebra.Com's Answer #593774 by Boreal(15235)\"\" \"About 
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smaller=x
\n" ); document.write( "larger is 2x-1
\n" ); document.write( "2x^2 + (2x-1) =39\r
\n" ); document.write( "\n" ); document.write( "2x^2+2x -1-39=0\r
\n" ); document.write( "\n" ); document.write( "2x^2+2x-40=0; divide out a 2.\r
\n" ); document.write( "\n" ); document.write( "x^2+x-20=0\r
\n" ); document.write( "\n" ); document.write( "(x+5)(x-4)=0\r
\n" ); document.write( "\n" ); document.write( "x= -5. 4\r
\n" ); document.write( "\n" ); document.write( "Try 4
\n" ); document.write( "Larger is 9
\n" ); document.write( "32+7=39 ;; yes\r
\n" ); document.write( "\n" ); document.write( "Try -5
\n" ); document.write( "Larger is -11\r
\n" ); document.write( "\n" ); document.write( "25*2 - 11=39\r
\n" ); document.write( "\n" ); document.write( "Two solutions work, 4, and -5\r
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