document.write( "Question 971235: the larger of two integers is 1 less than twice the smaller. if twice the square of the smaller is increased by the larger,the result is 39 \n" ); document.write( "
Algebra.Com's Answer #593774 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! smaller=x \n" ); document.write( "larger is 2x-1 \n" ); document.write( "2x^2 + (2x-1) =39\r \n" ); document.write( "\n" ); document.write( "2x^2+2x -1-39=0\r \n" ); document.write( "\n" ); document.write( "2x^2+2x-40=0; divide out a 2.\r \n" ); document.write( "\n" ); document.write( "x^2+x-20=0\r \n" ); document.write( "\n" ); document.write( "(x+5)(x-4)=0\r \n" ); document.write( "\n" ); document.write( "x= -5. 4\r \n" ); document.write( "\n" ); document.write( "Try 4 \n" ); document.write( "Larger is 9 \n" ); document.write( "32+7=39 ;; yes\r \n" ); document.write( "\n" ); document.write( "Try -5 \n" ); document.write( "Larger is -11\r \n" ); document.write( "\n" ); document.write( "25*2 - 11=39\r \n" ); document.write( "\n" ); document.write( "Two solutions work, 4, and -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |