document.write( "Question 82784: PROBLEM\r
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document.write( "A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old is each one now?
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document.write( "Woman= h+5
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document.write( "Husband= h
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document.write( "Daughter=h+5/10(I think)
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document.write( " 100 \r
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document.write( "(h+5)+(h)+(h+5/10)=100
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document.write( " 2h+5+(h+5/10)=100
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document.write( " 3h+10=1000
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document.write( " 3h/3=990/3
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document.write( " h=330\r
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document.write( "My question is what did i do wrong I know that this is way too high of a number and I can't figure out where I went wrong. Thanks
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Algebra.Com's Answer #59377 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let w=woman, h=husband, d=daughter\r \n" ); document.write( "\n" ); document.write( "Set up the following equations:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So in 14 years the woman's age is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 14 years the husband's age is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and in 14 years the daughter's age is \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Adding these together we get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the woman is 30 years old. In 14 years she will be 44 years old. The husband's age is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the husband is 25 now and in 14 years he will be 39. Finally the daughter's age is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the daughter is 3 years old now and in 14 years will be 17 years old. So if we add everyone's future age (ie their age in 14 years) together we get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This verifies our answer. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "note: you forgot to factor in the 14 year time lapse. That would explain the large age answer you got. Also, I'm not sure how you got Daughter=h+5/10 \n" ); document.write( " |