document.write( "Question 971197: Please help me am struggling with logarithms: 1log5^x=log5^(x-1) \n" ); document.write( "
Algebra.Com's Answer #593755 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
The expression within each log function would be equal:\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Alog%28%285%5Ex%29%29=log%28%285%5E%28x-1%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5Ex=5%5E%28x-1%29\"
\n" ); document.write( "and here, the exponents would be equal because each member uses the same base.\r
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\n" ); document.write( "\n" ); document.write( "\"x=x-1\"
\n" ); document.write( "and that is impossible.
\n" ); document.write( "NO SOLUTION
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