document.write( "Question 82783: How do you put [x=y^2+8y+13] into vertex form and how do you graph it?
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Algebra.Com's Answer #59370 by stanbon(75887)\"\" \"About 
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How do you put [x=y^2+8y+13] into vertex form and how do you graph it?
\n" ); document.write( "Square the y-terms to get:\r
\n" ); document.write( "\n" ); document.write( "x=y^2+8y+16+13-16\r
\n" ); document.write( "\n" ); document.write( "x=y^2+8y+16-3
\n" ); document.write( "x+3 = (y+4)^2\r
\n" ); document.write( "\n" ); document.write( "Vertex at (-3,-4)
\n" ); document.write( "x-intercept at 13
\n" ); document.write( "y-intercepts:
\n" ); document.write( "y = [-8+-sqrt(8^2-4*13)]/2
\n" ); document.write( "y = [-8+-2sqrt3]/2
\n" ); document.write( "y = (-4+sqrt3) or y = -4-sqrt3
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\n" ); document.write( "The parabola opens to the right; has vertes, x-intercept, and y-intercepts
\n" ); document.write( "as indicated.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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