document.write( "Question 971039: Trying to help my pre-calc student--\r
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Algebra.Com's Answer #593640 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!
Trying to help my pre-calc student--\r
\n" ); document.write( "\n" ); document.write( "Solve:\r
\n" ); document.write( "\n" ); document.write( "ln(5-x) + ln(3) = ln(6)\r
\n" ); document.write( "\n" ); document.write( "THANKS!
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ln (5 - x) + ln 3 = ln 6
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document.write( "ln 3(5 - x) = ln 6 ---- Applying the following: 
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document.write( "3(5 - x) = 6 ---------- Applying the following:  becomes  
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document.write( "15 - 3x = 6
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document.write( "- 3x = 6 - 15
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document.write( "- 3x = - 9
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document.write( "x = , or 
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document.write( "Be reminded that you're not finished yet. The value(s) you get for the variable should make the ORIGINAL equation
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document.write( "TRUE, so 3 should be substituted, for x, in the original equation: ln (5 - x) + ln 3 = ln 6, to determine if the
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document.write( "value for x is correct. This is a MUST since there are times when a value may prove to be an EXTRANEOUS solution. 
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document.write( "I'll leave this up to you. \n" );
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