document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971062>Question 971062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7.	Two trains, one travelling 15 km/hr faster than the other, leave the same station at the same time, one travelling east and the other west. At the end of 6 hours they are 570 km apart. What is the speed of each train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593634 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Speed of slower train=x<BR>\n" );
document.write( "Speed of faster train = x + 15\r<BR>\n" );
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document.write( "6{x +(x+15)}=570  speed units km/h  6 is hours, so distance will be km.\r<BR>\n" );
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document.write( "divide by 6 and collect terms\r<BR>\n" );
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document.write( " (2x+15)=95<BR>\n" );
document.write( "subtract 15 from both sides<BR>\n" );
document.write( "2x=80<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x=40 km/h (slower)<BR>\n" );
document.write( "x+15= 55 km/h (faster)\r<BR>\n" );
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document.write( "6 hours<BR>\n" );
document.write( "slower train 6*40=240 km<BR>\n" );
document.write( "faster train 5+55=330<BR>\n" );
document.write( "Total is sum, or 570.<BR>\n" );
document.write( " </SPAN>\n" );
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