document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=971001>Question 971001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 9:00 in the mornong, two bicyclists heading opposite directions pass each other on a bicycle path. THe bicyclist headong north is going 4km/h faster than the other guy. AT 10:30, they ate 39km apart. Whats the rate of the two bicylists? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593621 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slower cyclist is x kph<BR>\n" );
document.write( "faster cyclist is x+4 kph \r<BR>\n" );
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document.write( "in 1.5 hours, their distance is 39 km\r<BR>\n" );
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document.write( "39 km/1.5 hours is 26 kph\r<BR>\n" );
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document.write( "x+ (x+4) =26\r<BR>\n" );
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document.write( "2x +4=26<BR>\n" );
document.write( "2x=22\r<BR>\n" );
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document.write( "x=11\r<BR>\n" );
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document.write( "x=4=15\r<BR>\n" );
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document.write( "They are traveling apart at 26 kph; in 1.5 hours they will be 39 km apart.\r<BR>\n" );
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document.write( "The slower is traveling at 11kph; the faster at 15 kph. </SPAN>\n" );
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