document.write( "Question 970983: Find the general form of an equation of the hyperbola whose vertices are the foci of the ellipse x2/100 + y2/64 =1 and whose foci are the vertices of the ellipse. \n" ); document.write( "
Algebra.Com's Answer #593617 by MathLover1(20850)\"\" \"About 
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Find the general form of an equation of the hyperbola \r
\n" ); document.write( "\n" ); document.write( "whose vertices are the foci of the ellipse and whose foci are the vertices of the ellipse.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F100+%2B+y%5E2%2F64+=1+\"\r
\n" ); document.write( "\n" ); document.write( "=> \"a%5E2=100\", so \"a=10\" and \"a=-10\"\r
\n" ); document.write( "\n" ); document.write( "=> \"b%5E2=64\", so \"b=8\"
\n" ); document.write( "\"c=sqrt%28a%5E2-b%5E2%29=sqrt%28100-64%29=sqrt%2836%29\"\r
\n" ); document.write( "\n" ); document.write( "so, \"c=6\" or \"c=-6\"\r
\n" ); document.write( "\n" ); document.write( "foci: at (\"-c\", \"0\") and (\"c\", \"0\")=>(\"-6\", \"0\") and (\"6\", \"0\")\r
\n" ); document.write( "\n" ); document.write( "vertices: (\"-a\",\"+0\") and (\"a\", \"0\")=> (\"-10\",\"+0\") and (\"10\", \"0\")\r
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\n" ); document.write( "\n" ); document.write( "then hyperbola has
\n" ); document.write( " foci:
\n" ); document.write( "(\"sqrt%28a%5E2%2Bb%5E2%29\", \"0\") and (\"-sqrt%28a%5E2%2Bb%5E2%29\", \"0\")
\n" ); document.write( "(\"10\",\"+0\") and (\"-10\", \"0\") \r
\n" ); document.write( "\n" ); document.write( "vertices:
\n" ); document.write( "(\"a\", \"0\") and (\"-a\", \"0\")
\n" ); document.write( " (\"6\",\"0\") and (\"-6\", \"0\")\r
\n" ); document.write( "\n" ); document.write( "since \"sqrt%28a%5E2%2Bb%5E2%29=10\" and \"a=6\"=> then \"b\" is\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%286%5E2%2Bb%5E2%29=10\"}
\n" ); document.write( "\"36%2Bb%5E2=100\"
\n" ); document.write( "\"b%5E2=100-36\"
\n" ); document.write( "\"b=8\" or \"b=-8\"\r
\n" ); document.write( "\n" ); document.write( "and your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F36-y%5E2%2F64=1\"\r
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