document.write( "Question 970844: Hello,\r
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document.write( "looking for a bit of guidance with Laplace transforms. Could I please be shown how to:\r
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document.write( "1. Use the Laplace transform to solve for X: 8 dx/dt + 4 given x=0 @ t=0\r
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document.write( "2. Use the Laplace Integral: L[f(t)]=F(s)=∫_0^∞ e^(-st) f(t)dt to find the transform of the voltage shown in an exponential decay for t≥0.\r
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document.write( "Thanks a lot in advance. \n" );
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Algebra.Com's Answer #593606 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 1) solve for X: 8 dx/dt + 4 given x=0 @ t=0 \n" ); document.write( "I assume you mean 8 * (dx/dt) + 4 = 0 \n" ); document.write( "******************************************* \n" ); document.write( "The general rule of Laplace transforms is\r \n" ); document.write( "\n" ); document.write( "L[x'] = sL[x(t)] - x(0)\r \n" ); document.write( "\n" ); document.write( "So taking the laplace transform of both sides \n" ); document.write( "********************************************** \n" ); document.write( "L[8 * x' + 4] = L[0] \n" ); document.write( "L[8x'] + L[4] = L[0] \n" ); document.write( "note that L[c] = c/s and L[0] = 0 \n" ); document.write( "8L[x'] + 4/s = 0 \n" ); document.write( "8*(sL[x(t)] - x(0)) + 4/s = 0 \n" ); document.write( "since we are given x(0) = 0 \n" ); document.write( "8sL[x(t)] + 4/s = 0 \n" ); document.write( "divide both sides of = by 4 \n" ); document.write( "2sL[x(t)] + 1/s = 0 \n" ); document.write( "2sL[x(t)] = -1/s \n" ); document.write( "divide both sides of = by s \n" ); document.write( "2L[x(t)] = -1/(s^2) \n" ); document.write( "divide both sides of = by 2 \n" ); document.write( "L[x(t)] = -1/(2*s^2) \n" ); document.write( "************************************************ \n" ); document.write( "2) L[f(t)]=F(s)=∫_0^∞ e^(-st) f(t)dt to find the transform of the voltage shown in an exponential decay for t≥0. \n" ); document.write( "voltage shown? \n" ); document.write( " \n" ); document.write( " |