document.write( "Question 970939: A circle has an equation\r
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\n" ); document.write( "\n" ); document.write( "Graph the circle using the center (h,k) and radius r. Find the intercepts, if any, of the graph. \n" ); document.write( "
Algebra.Com's Answer #593581 by MathTherapy(10552)\"\" \"About 
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A circle has an equation\r
\n" ); document.write( "\n" ); document.write( "x^2+y^2-3x-4y+4=0\r
\n" ); document.write( "\n" ); document.write( "Graph the circle using the center (h,k) and radius r. Find the intercepts, if any, of the graph.
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\"x%5E2+%2B+y%5E2+-+3x+-+4y+%2B+4+=+0\"
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document.write( "\"x%5E2+-+3x+%2B+y%5E2+-+4y+=+-+4\"
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document.write( "\"%28x%5E2+-+3x%29+%2B+%28y%5E2+-+4y%29+=+-+4\" ------- Grouping variables
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document.write( "\"%28x%5E2+-+3x+%2B+9%2F4%29+%2B+%28y%5E2+-+4y+%2B+4%29+=+-+4+%2B+9%2F4+%2B+4\"
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document.write( "\"%28x+-+3%2F2%29%5E2+%2B+%28y+-+2%29%5E2+=+9%2F4\"
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document.write( "Since the center-radius form of the equation of a circle is: \"%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2\",
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document.write( "it's obvious that the center, or (h, k) = (\"3%2F2\", 2)
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document.write( "Since \"r%5E2+=+9%2F4\", then r, or radius = \"sqrt%289%2F4%29\", or \"3%2F2\"
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document.write( "Based on this info, you should be able to graph the circle. \n" );
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