document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970867>Question 970867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use demoivres theorem to find the indicated power of the complex number <BR>\n" );
document.write( "  [2&#8730;2(cos(3&#960;/7)+isin(3&#960;/7)]^&#8722;4  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593536 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use demoivres theorem to find the indicated power of the complex number <BR>\n" );
document.write( "[2&#8730;2(cos(3&#960;/7)+isin(3&#960;/7)]^&#8722;4 <BR>\n" );
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document.write( "!st: Find the 4th power of 2sqrt(2)cis(3pi/7)<BR>\n" );
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document.write( "r = (2sqrt(2))^4 = (2^(3/2))^4 = 2*6 = 64<BR>\n" );
document.write( "theta = (3/7)pi<BR>\n" );
document.write( "n = 4<BR>\n" );
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document.write( "Ans:  64cis(12pi/7)<BR>\n" );
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document.write( "2nd: Find the inverse<BR>\n" );
document.write( "(1/64)cis(-12pi/7)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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