document.write( "Question 970834: : One study on managers’ satisfaction with management tools reveals that 59% of all managers use self-directed work teams as a management tool. Suppose 70 managers selected randomly in the United States are interviewed. What is the probability that fewer than 35 use self-directed work teams as a management tool? \n" ); document.write( "
Algebra.Com's Answer #593528 by Boreal(15235)\"\" \"About 
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One sample proportion.\r
\n" ); document.write( "\n" ); document.write( "Fewer than 35 is fewer than 0.50\r
\n" ); document.write( "\n" ); document.write( "z= 0.50-0.59/sqrt [(.59)(.41)/70] ;; It is p of sample - p comparing with in numerator.
\n" ); document.write( "In denominator, it is sqrt p(1-p)/n, where the p's are the second, not the sample, and n=sample size.\r
\n" ); document.write( "\n" ); document.write( "z= -0.09/0.0588\r
\n" ); document.write( "\n" ); document.write( "z < -1.531\r
\n" ); document.write( "\n" ); document.write( "p=0.06 (0.0629)
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