document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970868>Question 970868</A>: <I><SPAN STYLE=\"word-break: break-all;\">  what is the equation of the line perpendicular to y = -5/3x + 11 1/3 and containing P (-2, 3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593495 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the equation of the line perpendicular to y = -5/3x + 11 1/3 and containing P (-2, 3)<BR>\n" );
document.write( "y = -5/3x + 11 1/3<BR>\n" );
document.write( "slope=-5/3<BR>\n" );
document.write( "slope of perpendicular line=3/5 (negative reciprocal)<BR>\n" );
document.write( "equation of perpendicular line:<BR>\n" );
document.write( "y=3x/5+b solve for b using coordinates of given point P on the line<BR>\n" );
document.write( "3=3*(-2)/5+b<BR>\n" );
document.write( "15/5 +6/5=b<BR>\n" );
document.write( "b=21/5<BR>\n" );
document.write( "equation: y=3x/5+21/5 </SPAN>\n" );
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