document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970791>Question 970791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3sqrt6(sqrt10-sqrt3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593443 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You distribute the 3 sqrt (6), and you recognize that sqrt (6) * sqrt (10)= sqrt (60)\r<BR>\n" );
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document.write( "The problem is 3 sqrt (60)- 3 sqrt (18)\r<BR>\n" );
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document.write( "Then you try to factor a perfect square out.  sqrt (60)=sqrt (4)*sqrt(15)=2 sqrt (15)\r<BR>\n" );
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document.write( "sqrt (18)= 3 sqrt (2)\r<BR>\n" );
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document.write( "So the second line become 6 sqrt (15)-9 sqrt (2).  These cannot be simplified, although one could factor out a 3[2 sqrt (15)-3 sqrt (2)]\r<BR>\n" );
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document.write( "Calculator     7.348*  (3.16-1.73)=23.22-12.71\r<BR>\n" );
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document.write( "6 sqrt (15)-9 sqrt (2)=23.24-12.73  ;  These are basically the same with rounding error. </SPAN>\n" );
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