document.write( "Question 970764: After t hours on a particular day, a freight train is s(t)=−17.98t+16.732t^2-0.78t^3 miles due east of its starting point (for 0≤t≤18).
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Algebra.Com's Answer #593424 by Alan3354(69443)\"\" \"About 
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After t hours on a particular day, a freight train is
\n" ); document.write( "s(t)= -17.98t + 16.732t^2 - 0.78t^3 miles due east of its starting point (for 0≤t≤18).
\n" ); document.write( "a) Where is the train (both distance and direction from starting point) after 9 hours?
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\n" ); document.write( "s(t)= -17.98t + 16.732t^2 - 0.78t^3
\n" ); document.write( "Sub 9 for t
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\n" ); document.write( "s(9)= -17.98*9 + 16.732*9^2 - 0.78*9^3
\n" ); document.write( "Just arithmetic.
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