document.write( "Question 970089: Computer A can process a megabyte of data in 15 seconds less time than computer B. Working together computers A and B can process a megabyte of data in 18 seconds. How long does it take each Computer to process a megabyte of data? \n" ); document.write( "
Algebra.Com's Answer #593370 by lwsshak3(11628)\"\" \"About 
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Computer A can process a megabyte of data in 15 seconds less time than computer B. Working together computers A and B can process a megabyte of data in 18 seconds. How long does it take each Computer to process a megabyte of data?
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\n" ); document.write( "let x=time computer B can process a megabyte of data
\n" ); document.write( "1/x=its work rate
\n" ); document.write( "x-15=time computer A can process a megabyte of data
\n" ); document.write( "1/(x-15)=its work rate
\n" ); document.write( "18=time computer A and B working together can process a megabyte of data
\n" ); document.write( "1/18=its work rate
\n" ); document.write( "..
\n" ); document.write( "sum of indv. work rates=work rate working together
\n" ); document.write( "\"1%2Fx%2B1%2F%28x-15%29=1%2F18\"
\n" ); document.write( "lcd:18x(x-15)
\n" ); document.write( "18(x-15)+18x=x(x-15)
\n" ); document.write( "18x-270+18x=x^2-15x
\n" ); document.write( "x^2-51x+270=0
\n" ); document.write( "(x-6)(x-45)=0
\n" ); document.write( "x=45
\n" ); document.write( "x-15=30
\n" ); document.write( "time computer B can process a megabyte of data=45 sec
\n" ); document.write( "time computer A can process a megabyte of data=30 sec \n" ); document.write( "
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