document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=970190>Question 970190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A piece of wire 35/3 in long is to be divided into two parts, such as that one part is 2/3 that of. The other. Find the length of the shorter piece.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593368 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A piece of wire 35/3 in long is to be divided into two parts, such as that one part is 2/3 that of. The other. Find the length of the shorter piece.<BR>\n" );
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document.write( "let x=length of shorter piece<BR>\n" );
document.write( "(35/3)-x=length of longer piece<BR>\n" );
document.write( "x=2/3(35/3-x)<BR>\n" );
document.write( "x=70/9-2x/3<BR>\n" );
document.write( "lcd:9<BR>\n" );
document.write( "9x=70-6x<BR>\n" );
document.write( "15x=70<BR>\n" );
document.write( "x=14/3 <BR>\n" );
document.write( "length of shorter piece=14/3=4 2/3 inches </SPAN>\n" );
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