document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29546>Question 29546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the multiplication and the addition principles. Ex.8(2t+1)>4(7t+7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #593331 by </B><A HREF=/tutors/aboutme.mpl?userid=JimMarshall><B>JimMarshall(82)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimMarshall><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimMarshall><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=593331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8(2t+1)>4(7t+7)<BR>\n" );
document.write( "Dividing by 4>0<BR>\n" );
document.write( "(Dividing by a positive quantity does not alter the inequality and therefore greater than remains greater than)<BR>\n" );
document.write( "2(2t+1>7t+7<BR>\n" );
document.write( "4t+2 > 7t +7<BR>\n" );
document.write( "4t-7t > 7-2 <BR>\n" );
document.write( "(grouping like terms by transferring terms,change side then change sign)<BR>\n" );
document.write( "-3t > 5<BR>\n" );
document.write( "(Dividing by (-3) and dividing by a negative quantity alters the inequality and therefore greater than becomes less than)<BR>\n" );
document.write( "t < 5/(-3)<BR>\n" );
document.write( "That is t< (-5/3) Ans </SPAN>\n" );
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